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Mastering Arithmetic for GCSE Success

Introduction

Arithmetic forms the foundation of GCSE Maths, covering everything from basic calculations to real-life applications. These skills are critical for understanding advanced topics like algebra, geometry, and statistics.

In this article, we’ll focus on:

  1. Fractions, Decimals, and Percentages.
  2. Simplifying and calculating accurately.
  3. Real-life applications of arithmetic.
  1. Fractions: Simplifying and Calculating

Fractions represent a part of a whole and are crucial for GCSE success.

Simplifying Fractions

To simplify fractions:

  1. Divide the numerator and denominator by their highest common factor (HCF).

Example: Simplify \frac{18}{24}.

  • HCF of 18 and 24 is 6.

    \[ \frac{18 \div 6}{24 \div 6} = \frac{3}{4}. \]

Adding and Subtracting Fractions

Fractions must have the same denominator.

Example: \frac{1}{4} + \frac{2}{3}

  1. Find a common denominator: \text{LCM of 4 and 3} = 12.
  2. Rewrite fractions: \frac{3}{12} + \frac{8}{12} = \frac{11}{12}.

Multiplying and Dividing Fractions

  • Multiply: Multiply the numerators and denominators directly.
  • Divide: Multiply by the reciprocal of the second fraction.

Example:

    \[ \frac{2}{5} \div \frac{3}{4} = \frac{2}{5} \times \frac{4}{3} = \frac{8}{15}. \]

  1. Decimals: Converting and Calculating

Converting Fractions to Decimals

  • Divide the numerator by the denominator.

Example: Convert \frac{7}{8} to a decimal:

    \[ 7 \div 8 = 0.875. \]

Rounding Decimals

  • Round to a specified number of decimal places or significant figures.

Example: Round 3.4567 to 2 decimal places: 3.46.

  1. Percentages: Finding Parts and Whole

Finding Percentages of a Number

Example: Find 20% of 80.

  1. Convert to a decimal: 20\% = 0.2.
  2. Multiply: 0.2 \times 80 = 16.

Finding the Whole Given a Percentage

Example: 25% of a number is 50. What is the number?

  1. Rewrite as an equation: 0.25 \times x = 50.
  2. Solve: x = 50 \div 0.25 = 200.
  1. Real-Life Applications

  • Money Problems: Working out discounts, VAT, and interest.
  • Measurements: Scaling recipes or resizing shapes.

Practice Question

Question: A coat is discounted by 15%, reducing the price to £85. What was the original price?

Solution:

  1. Let the original price be x.
  2. Equation: x - 0.15x = 85.
  3. Simplify: 0.85x = 85.
  4. Solve: x = \frac{85}{0.85} = 100.

Answer: The original price was £100.

Conclusion

Mastering arithmetic is essential for GCSE Maths and beyond. Practice simplifying fractions, calculating percentages, and applying these skills to real-life scenarios to build confidence.

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