Table of Contents
ToggleCalculus: Differentiation and Its Applications
What Is Differentiation?
Differentiation is a fundamental concept in calculus that deals with the rate of change of a function. The derivative represents the slope or instantaneous rate of change at a specific point.
The Derivative: Basic Definition
The derivative of a function \( f(x) \) is defined as:
\[ f'(x) = \lim_{\Delta x \to 0} \frac{f(x + \Delta x) – f(x)}{\Delta x} \]
This limit gives the slope of the tangent line to \( f(x) \) at point \( x \).
Basic Differentiation Rules
Power Rule
If \( f(x) = x^n \), then:
\[ f'(x) = n \cdot x^{n-1} \]
Example:
\[ \text{If } f(x) = x^3, \text{ then } f'(x) = 3x^2 \]
Constant Rule
If \( f(x) = c \) (where \( c \) is constant):
\[ f'(x) = 0 \]
Sum and Difference Rule
For \( f(x) = g(x) \pm h(x) \):
\[ f'(x) = g'(x) \pm h'(x) \]
Product Rule
For \( f(x) = u(x) \cdot v(x) \):
\[ f'(x) = u'(x)v(x) + u(x)v'(x) \]
Quotient Rule
For \( f(x) = \frac{u(x)}{v(x)} \):
\[ f'(x) = \frac{v(x)u'(x) – u(x)v'(x)}{[v(x)]^2} \]
Applications of Differentiation
Finding Tangents to Curves
The derivative gives the slope of the tangent line at any point on a curve.
Example: Find the tangent to \( y = x^2 \) at \( x = 3 \).
- Differentiate: \( y’ = 2x \)
- Evaluate at \( x = 3 \): \( y’ = 6 \)
- Equation: \( y – 9 = 6(x – 3) \) or \( y = 6x – 9 \)
Velocity and Acceleration
For position \( s(t) \):
- Velocity: \( v(t) = \frac{ds}{dt} \)
- Acceleration: \( a(t) = \frac{dv}{dt} = \frac{d^2s}{dt^2} \)
Optimization Problems
Critical points (maxima/minima) occur where \( f'(x) = 0 \).
Example Problem
Problem: Find critical points of \( f(x) = 3x^4 – 4x^3 + 2x^2 – 5 \).
Solution:
- Differentiate:
\[ f'(x) = 12x^3 – 12x^2 + 4x \] - Set \( f'(x) = 0 \):
\[ 4x(3x^2 – 3x + 1) = 0 \] - Only real solution: \( x = 0 \)
Common Mistakes
- Misapplying the Power Rule (e.g., forgetting to subtract 1 from the exponent).
- Confusing Product Rule with Sum Rule.
- Incorrectly applying the Quotient Rule numerator order.
Practice Questions
- Differentiate \( f(x) = 5x^3 + 2x^2 – x + 7 \).
- Find the tangent to \( y = x^3 – 4x^2 + 2x \) at \( x = 2 \).
- Given \( s(t) = t^2 – 4t + 5 \), find velocity at \( t = 3 \).




